4+5								9
4+3*2								10
if(pi)(1)							1
1\t{arg1+1}; t(1)						2
1\f{ifelse (arg1 <= 1) (1) (f(arg1-1) * arg1) };f(10)		3628800
1\f2{r=arg1;while (arg1>1) (arg1=arg1-1;r=r*arg1);r};f2(10)	3628800
1\g{1\r{arg1*2} ; arg1+r(arg1)}; g(5)				15
5/0								(5/0)
4-7								-3
1\t2{arg1=arg1+1;arg1};t2(2)					3
4+2/3								14/3
10.1!								(10.1!)
4^(4/3)								6.34960420787
4^2.1								18.37917368
(78+8467i)*(-88754+8784i)			(-81296940+-750794966i)
